4[2t-(3-t)+5]=4(1-x)

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Solution for 4[2t-(3-t)+5]=4(1-x) equation:


Simplifying
4[2t + -1(3 + -1t) + 5] = 4(1 + -1x)
4[2t + (3 * -1 + -1t * -1) + 5] = 4(1 + -1x)
4[2t + (-3 + 1t) + 5] = 4(1 + -1x)

Reorder the terms:
4[-3 + 5 + 2t + 1t] = 4(1 + -1x)

Combine like terms: -3 + 5 = 2
4[2 + 2t + 1t] = 4(1 + -1x)

Combine like terms: 2t + 1t = 3t
4[2 + 3t] = 4(1 + -1x)
[2 * 4 + 3t * 4] = 4(1 + -1x)
[8 + 12t] = 4(1 + -1x)
8 + 12t = (1 * 4 + -1x * 4)
8 + 12t = (4 + -4x)

Solving
8 + 12t = 4 + -4x

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '-8' to each side of the equation.
8 + -8 + 12t = 4 + -8 + -4x

Combine like terms: 8 + -8 = 0
0 + 12t = 4 + -8 + -4x
12t = 4 + -8 + -4x

Combine like terms: 4 + -8 = -4
12t = -4 + -4x

Divide each side by '12'.
t = -0.3333333333 + -0.3333333333x

Simplifying
t = -0.3333333333 + -0.3333333333x

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